Question

In a AABC. if <C = 90°, prove that sin2 A + sin2 B =1.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

In triangle ABC :

sin²A=(BC/AB)²

sin²B=(AC/AB)²

sin²A+sin²B= (BC/AB)²+(AC/AB)²

= BC²+AC²/AB²

BUT BY PGT IN TRIANGLE ABC,

AB²=BC²+AC²

SO, AB²/AB²=1

=RHS

HENCE PROVED

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