Question

In a AABC, the ratio of ZBAC and ZABC is 6:7 and 2C = 50. Find the value of BAC and ABC​

Answer 1

Answer:

Here, we can see that ∠BAC∠BAC is bisected by AD where AD touches BC at D. BC=BD+DCBC=BD+DCwhere, BC=3cmBC=3cm. We also have the values of adjacent sides AB=6cmAB=6cmand AC=5cmAC=5cm.

These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:

ABBD=ACDCABBD=ACDC

⇒DC=AC∗BDAB=5∗36=2.5cm⇒DC=AC∗BDAB=5∗36=2.5cm

Happy math!!

Answer 2

Answer:

<BAC=60deegre <ABC=70degree