Question

In a ABC, ∠ = 30° and ∠ = 70° and the bisectors of ∠ and ∠ meet at O. Find ∠ .​

Answer 1

Answer:

In △BOC,

∠BOC+∠OBC+∠OCB=180 (OB and OC bisect ∠B and ∠C respectively)

∠BOC+

2

1

∠B+

2

1

∠C=180

∠BOC=180−

2

1

(∠B+∠C)

∠BOC=180−

2

1

(180−∠A)

∠BOC=180−

2

1

(180−70)

∠BOC=180−90+35

∠BOC=125

∘