Question

in a ∆ABC, A(1,4),B(-3,2) and C(1,6) if AD is the median of ∆ABC then AD =____ units​

Answer 1

Answer:

2 units

Step-by-step explanation:

To find the coordinate of D;-

D is the midpoint of BC

Coordinate of D=

$( \frac{ - 3 + 1}{2} ,( \frac{2 + 6}{2})$

Coordinate of D=(-1,4)

Now,

To find the length of AD;-

 = √[(Y2−Y1)²+(X2−X1)²]

= √[ (4-4)²+(-1-1)² ]

= 2

Hence, we get AD= 2 units