Question

In a ∆ABC , ∠A + ∠B = 110°, ∠C + ∠A = 135° , Find ∠A​

Answer 1

Answer:

$in \: a \: triangle \: abc \\ < a + < b = {110}^{o} \\ < a + < c = {135}^{o}$

That is given

Property of triangle the sum all angle is 180 degree therefor

$< a + < b + < c = {180}^{o} \\ {110}^{o} + < c = {180}^{o} \\ < c = {70}^{o} \\ < c + < a = {135}^{o} \\ < a = {65}^{o}$

That is your answer I hope this is helpful for you