In a ABC A + B = 125 and B + C = 150Find all the
angle of ABC
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Answered by
1
Answer:
A + B = 125 , B + C = 150
A+B+C = 180⁰( angle sum property of triangle)
125⁰+C = 180⁰
C = 180⁰-125⁰
C = 55⁰
B + C = 150⁰
B+55⁰=150⁰
B = 150⁰-55⁰
B = 95⁰
A + B = 125⁰
A+95⁰ = 125⁰
A = 125⁰-95⁰
A = 35⁰
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Answered by
0
<A+B=125
=A=125-B
<B+C=150
=C=150-B
WE KNOW THAT THE ANGLES OF TRIANGLE =180°
A+B+C=180°
(125-B)+B+(150-B)=180°
125- B+B+150-B=180°
275-B=180°
-B=180-275
-B=-95
THEN B =95
A=125-95
A=30
C=150-B
C=150-95
C=55
HENCE,A=30,B=95,C=55
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