In a ∆abc,a-b=33 and b-c=18 find the measure of each angle of the triangle
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a-b=33 .....(1)
b-c=18. .....(2)
a+b+c=180.....(3(
add (2) and (3)
a+2b=198............(4)
subtract (1) from (4)
(a+2b)-a+b=198-33
3b=165
b=55
from (1)
a=b+33=55+33=88
from (2)
c=b-18=55-18=37
b-c=18. .....(2)
a+b+c=180.....(3(
add (2) and (3)
a+2b=198............(4)
subtract (1) from (4)
(a+2b)-a+b=198-33
3b=165
b=55
from (1)
a=b+33=55+33=88
from (2)
c=b-18=55-18=37
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