Question

In a ∆ ABC ; ∠A = x 0 ; ∠B = (3x - 2)0 ; ∠C = y 0 . Also ∠C - ∠B = 9 0 . Find the three angles.

Answer 1

Answer:

25° , 73° , 82°  

Step-by-step explanation:

In Δ ABC : ∠A + ∠B + ∠C = 180°

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∠A = x° ; ∠B = (3x - 2)° ; ∠C = y°

∠C - ∠B = 9° ⇒ ∠C = ∠B + 9° = (3x - 2)° + 9°

(x + 3x - 2 + 3x + 7)° = 180°

7x + 5 = 180

7x = 175

x = 25°

∠A = 25°

∠B = 73°

∠C = 82°

(25 + 73 + 82)° = 180°

Answer 2

Answer:

A= 13.4, B= 38.2, C= 128.4

Step-by-step explanation:

A+B+C=180 .....(1)

x+(3x-2)+y=180 ....(2)

Also, C-B=90

C=90+B

Substituting value of C in equation (2),

x+(3x-2)+90+ B= 180 ....(3)

but B= (3x-2), substituting in equation (3),

x+(3x-2)+90+(3x-2)=180

7x=94

x=13.4

(3x-2)=38.2

Substituting values of x & (3x-2) in equation (2),

y= 128.4