Question

In a ∆ ABC , AB = 15 cm , BC = 13 cm and AC = 14 cm. Find the area of ∆ ABC and hence its altitude on AC.​

Answer 1

Answer:

as per given AC is altitude so,

we know area of triangle= half × base × height

so that is equal ➡

1/2×13×14=91cm square units

Answer 2

Altitude= 12cm and area=84 sq. cm