Question

In A ABC, AB=6cm,BC =5cm, B=50°, ZA=3x° and in A
PQR,PQ=6CM,QR=5cm, _Q=50°, ZP=2x+20° then the measure of ZP is

Answer 1

Step-by-step explanation:

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.

Step 4: Join B4C and draw a line through B3, parallel to B4C intersecting BC at C′.

Step 5: Draw a line through C′ parallel to AC intersecting AB at A′.

The triangle A′BC′ is the required triangle.