Question

In A ABC,AB=6cm,BC =5cm, ZB=50°, ZA=3x° and in A
POR,PQ=6CM,QR=5cm, _ Q=50°, ZP=2x+20° then the measure of ZP is

Answer 1

answer--

BC

′

whose sides are

4

3

of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60

∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B

1

,B

2

,B

3

,B

4

on line segment BX.

Step 4: Join B

4

C and draw a line through B

3

, parallel to B

4

C intersecting BC at C

.

Step 5: Draw a line through C

′

parallel to AC intersecting AB at A

′

.

The triangle A

′

BC

′

is the required triangle.

Step-by-step explanation:

pls mark brainliest