Question

In a ∆ABC,AB=AC=8cm and angle A=90°.Calculate the area of ∆ABC​

Answer 1

Answer:

Area of triangle =

$\frac{1}{2} \times \: product \: of \: any \: 2 \: sides \times \: sine \: of \: included \: angle$

$\frac{1}{2} \times 8 \times 8 \times sin90 \\ 32 \times 1 \\ = 32cm {}^{2}$