In a ΔABC, AB=AC and D is the midpoint of BC.
a. Prove that ΔADB ≅ ΔADC b) Is ∠ B = ∠C? Give reasons
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Answer:
(a) In triangle ABD and ACD,
AD=AD
AB=AC
BC=CD [D is mid-point at BC]
(b) By using part a of the solution, we get
∴ △ABD≅△ACD ... SSS criterion
Angle b = angle c by (c.p.c.t)
hope this will help you
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