In a ∆ABC, AB= AC and < ACD =110⁰, Find all the three interior angles of the triangle.
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Answer:
40⁰
Step-by-step explanation:
AB = AC then <B = <C
<C + < ACD= 180 (LP)
<C = 180-110 = 70⁰
Therefore <B = 70⁰ <B + <A = 110⁰ ( Ex. A P)
<A = 110-70 = 40⁰
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