Question

In a ∆ abc,ab = ac and < b = 45° then find the value of < a, < c.

Answer 1

In a triangle abc,

ab= ac (given)

and <b= 45°

so, <c= 45° ( if the sides of a triangle are equal then their angles are also equal)

now,

<a + <b + <c =180° ( angle sum property)

<a + 45° + 45° = 180°

<a + 90° = 180°

<a = 180°- 90°

<a = 90°

Answer 2

Answer:

< a = 90° , < c = 90 °

It is an isosceles traingle so its opposite angles are always equal angle = 45°

According to angle some property a+b+c = 180°

a+45+45 = 180°

a = 180-90

a = 90°

AB = AC..

Step-by-step explanation:

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