In a ∆ABC, AB = AC, BAC = 800, then find ABC
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50° is the answer .....
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In a triangle ,
Sum of angles = 180°
x + x + 80° = 180°
2x + 80° = 180°
2x = 180° - 80°
=100°
x = 100° / 2
= 50°
So answer ,
Angle ABC is 50° .
Sum of angles = 180°
x + x + 80° = 180°
2x + 80° = 180°
2x = 180° - 80°
=100°
x = 100° / 2
= 50°
So answer ,
Angle ABC is 50° .
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