In a ΔABC , AD is the bisector of ∠A , meeting side BC at D.
(i) If BD = 2.5 cm, AB = 5 cm and AV = 4.2 cm, find DC.
(ii) If BD = 2 cm, AB = 5 cm and DC = 3 cm, find AC.
(iii) If AB = 3.5 cm, AC = 4.2 cm and DC = 2.8 cm, find BD.
(iv) If AB = 10 cm, AC = 14 cm and BC = 6 cm, find BD and DC.
(v) If AC = 4.2 cm, DC = 6 cm and BC = 10 cm, find AB.
(vi) If AB = 5.6 cm, AC = 6 cm and DC = 6 cm, find BC.
(vii) If AD = 5.6 cm, BC = 6 cm and BD = 3.2 cm, find AC.
(viii) If AB = 10 cm, AC = 6 cm and BC = 12 cm, find BD and DC.
Answers
Triangle
Step-by-step explanation:
Given: In a ΔABC , AD is the bisector of ∠A , meeting side BC at D.
So we know that AB/AC = BD/DC
(i) BD = 2.5 cm, AB = 5 cm and AC = 4.2 cm.
DC = AC * BD / AB = 2.5 * 4.2 /5 = 2.1cm
(ii) BD = 2 cm, AB = 5 cm and DC = 3 cm.
AC = AB * DC / BD = 5 * 3 / 2 = 15/2 = 7.5cm
(iii) AB = 3.5 cm, AC = 4.2 cm and DC = 2.8 cm.
BD = AB * DC / AC = 3.5 * 2.8 / 4.2 = 2.33cm
(iv) AB = 10 cm, AC = 14 cm and BC = 6 cm
BD/DC = AB/AC = 10/14 = 5/7
BD = 5/12 * 6 = 2.5cm
DC = 7/12 * 6 = 3.5cm
(v) AC = 4.2 cm, DC = 6 cm and BC = 10 cm
AB/4.2 = 4/6 (as BD = BC- DC)
AB = 2/3 *4.2 = 2.8cm
(vi) AB = 5.6 cm, AC = 6 cm and DC = 6 cm.
BD = DC * AB/AC = 6 * 5.6/ 6 = 5.6cm
BC = BD + DC = 5.6cm + 6 cm = 11.6cm
(vii) AB = 5.6 cm, BC = 6 cm and BD = 3.2 cm, find AC.
DC = BC - BD = 6 - 3.2 = 2.8cm
AC = AB * DC/BD = 5.6 * 2.8 / 3.2 = 4.9cm
(viii) AB = 10 cm, AC = 6 cm and BC = 12 cm
BD/DC = AB/AC = 10/6 = 5/3
BD = 5/8 * 12 = 7.5cm
DC = BC - BD = 12 - 7.5 = 4.5cm
AD is the bisector of ∠A , meeting side BC at D. => AB /AC = BD/CD
Step-by-step explanation:
In a ΔABC , AD is the bisector of ∠A , meeting side BC at D
=> AB /AC = BD/CD
(i) If BD = 2.5 cm, AB = 5 cm and AC = 4.2 cm, find DC.
=> 5/4.2 = 2.5/DC
=> DC = 2.1 cm
(ii) If BD = 2 cm, AB = 5 cm and DC = 3 cm, find AC.
=> 5/AC = 2/3
=> AC = 7.5 cm
(iii) If AB = 3.5 cm, AC = 4.2 cm and DC = 2.8 cm, find BD.
=> 3.5/4.2 = BD/2.8
=> BD = 7/3 cm
Find all other same way
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