In a ∆ABC , AD is the bisector of angle A , meeting side BC at D then if AD = 5.6cm , BC=6 cm and BD= 3.2 cm ,find AC
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CD=6-3.2=2.8
CD=2.8
AC^2+AD^2
=(6.5)^2+(2.8)^2
=31.36+7.84
=39.2
AC^2=39.2
=6.260
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