In A ABC, AD is the median and DE is
parallel to BA, where E is a point in AC.
Prove that BE is also a median.
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Since AD is the median of ΔABC, then BD = DC. Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem, ... Therefore, E is the mid point of AC. Hence, BE is the median of ΔABC.
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