Math, asked by barunshougaijam956, 7 months ago

In a ∆ABC, angle A = 100° and AB=AC,Find angle B and C​

Answers

Answered by Anonymous
1

Step-by-step explanation:

AB=AC

∠B=∠C [Angles opposite to equal sides are equal]

In △ABC,

∠A+∠B+∠C=180

o

100

o

+2∠B=180

o

∠B=40

o

Therefore,

∠B=∠C=40

o

Answered by directioner133
2

Answer:

∆ABC is an isosceles ∆

So, angle B = angle C

So 180°-100°=80° ( because 180° is total sum of a ∆)

So 80°/2= 40°

Hence Angle B & C = 40°

Thank & mark me brainliest

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