In A ABC Angle ACD is the exterior angle measuring 110° if Angle B = 30° find LA and L ACB A
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Answer:
We are given m∠B=40
o
m∠A=70
o
Now,
BD
is a straight ray
so, m∠ACB+m∠ACD=180
o
→(1)
In △ABC,m∠A+m∠B+m∠ACB=180
o
→(2)
From (1) & (2)
m∠A+m∠B=m∠ACD
so, m∠ACD=40
o
+70
o
m∠ACD=110
o
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