Question

in a ∆ABC angle B=90 and 3/4 tan A=1 then find sin c-cos c​

Answer 1

Step-by-step explanation:

in ∆ABC, B=90°

A+C=90

A=90-C

3/4tanA=1

tanA=4/3

tan(90-C)=4/3

cotC= 4/3

b/p=4/3

b=4 p=3

h²=p²+b²

h²=3²+4²

h²= 9+16

h²= 25

h= 5

sin c-cos c

p/h - b/h

3/5-4/5

-1/5

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