In A ABC, angle B=90. If AB = 11 and BC = 60.
find the perimeter of triangle ABC.
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1
Answer:
B=90
triangle ABC is a right angle
By Pythagoras theorem
AB^2+BC^2=AC^2
11^2+60^2=AC^2
121 +3600=AC^2
3721=AC^2
61=AC
AB+AC+BC=11+60+61=132
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Answered by
1
Answer:
132 is the answer which is proved in the above.
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