Math, asked by drishtichandrasen, 7 months ago

In A ABC, angle B=90. If AB = 11 and BC = 60.
find the perimeter of triangle ABC.​

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Answered by Anonymous
1

Answer:

B=90

triangle ABC is a right angle

By Pythagoras theorem

AB^2+BC^2=AC^2

11^2+60^2=AC^2

121 +3600=AC^2

3721=AC^2

61=AC

AB+AC+BC=11+60+61=132

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Answered by subhashree015behera
1

Answer:

132 is the answer which is proved in the above.

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