Question

IN a ABC,angle B=90degree,AB=5cm and (BC+AC)=25cm. find the values of sinA, cosA, cosecC and secC.
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Answer 1

Step-by-step explanation:

Given that,

BC+AC =25CM

AB=5CM

B=90°

SOLUTION:

LET BC BE X THEN,

X+AC=25

AC=25-X

BY PYTHAGORAS THEOREM, WE GET,

BC^2=AB^2+AC^2

X^2=5^2+(25-X) ^2

X^2=25+625+X^2-50X

50X=625

X=625÷50

X=13

BY THIS WE GET,

BC=13CM

AC=25-13=12CM

SO,

SIN A= 12/13

COS A=5/13

TAN A=12/5