In a ABC, angle BAC= 90°, AD is the altitude if AB = 2√5,BD = 4. Then find BC and AC.
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Answer:
Step-by-step explanation:
AB ^2 =BC.BD [using the corollary]
2 root 5^2 =BC×4
∴ 20/4 =BC
∴BC=5
Now, CD=BC−BD=5−4=1
AC^2 =BC.CD
⟹AC^2 =5×1
∴AC= Root 5
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