Question

In a ABC, angle C is 9° more than angle B, and angle B is 2° less than three times angle A . find the angles of the triangle​

Answer 1

Answer:

let the angle A=x

angles B= 3x-2°

angle c = angles B+9°=. 3x-2+9°

3x+7°

angle A + angle B + angle C= 180°

x+(3x-2)+(3x+7)= 180°

x+3x-2+3x+7=180°

7x+5°=180°

7x=180°-5°

7x=175°

x=175°/7

x=25°

angles A= 25°

angle B= 3x-2°

=3(25°)-2

=75°-2°=73°

angle B =73°

angle C= Angle B+9°

73°+9°

angles C =82°

25°,73°,82°

Answer 2

Answer:

sport don't know the answer ☹️☹️☹️