In a ∆ABC, angle C is obtuse and sin(A+B) =√3/2
and cos(A-B) = 1/√2. Then show that A= 52 1/2
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Answer:
given that
sin(A+B) = root 3/2 eqn(1)
A+B = 60
cos(A-B)= root 1/2 eqn(2)
A-B = 45
Solving eqn 1 and 2
2A = 105
A = 52 1/2
hence proved
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