Question

In a ∆ABC, angleB =90 degree, AB = 24 cm and BC = 7 cm.
Find (i) sin A (i) cos A (iii) sin C (iv) cos C.​

Answer 1

Answer:

Step-by-step explanation:

ac=hypotenuse

h^2=s^2+s^2

ac^2=24^2+7^2=25^2

ac=25

ab=perpendicular from angle c

bc=base from angle c

sin c=perpendicular /hypotenuse=24/25

cos c=base/hyp=7/25

ac=perpen from angle a

ab=base from angle a

sin a=per/hyp=7/25

cos a=base/hyp=24/25