In a ∠ABC, B = 90°, AB = 5 cm and BC = 7 cm. Find the value of tan A - cot C.
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Answered by
3
Given :
AB= 5 cm , BC= 7cm
tanA = perpendicular/base= BC/AB
tan A = 7/5
cot C= base / perpendicular= BC/AB
cot C= 7/5
tan A - cot C
7/5 - 7/5 = 0
tan A - cot C = 0
The value of tan A - cot C = 0
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Hope this will help you....
AB= 5 cm , BC= 7cm
tanA = perpendicular/base= BC/AB
tan A = 7/5
cot C= base / perpendicular= BC/AB
cot C= 7/5
tan A - cot C
7/5 - 7/5 = 0
tan A - cot C = 0
The value of tan A - cot C = 0
==================================================================================
Hope this will help you....
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Answered by
1
Hi friend,
Your answer:
tanA = perpendicular/base
= BC/AB
= 7/5
cot C = base / perpendicular
= BC/AB
= 7/5
Now,
tan A - cot C = 7/5 - 7/5 = 0
Hence, the value of tan A - cot C = 0
Hope it helps!
Your answer:
tanA = perpendicular/base
= BC/AB
= 7/5
cot C = base / perpendicular
= BC/AB
= 7/5
Now,
tan A - cot C = 7/5 - 7/5 = 0
Hence, the value of tan A - cot C = 0
Hope it helps!
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