Question

In a ∆ABC, ∠B=90° and AB = √3 and BC = 1 i) find AC ii) find angle C iii) find cosec A iv) find cos C​

Answer 1

Answer:

i) AC= 2

ii) angle C= 30°

iii) cosec A = 2

iv) cos C= 1/2

Step-by-step explanation:

I) AB=√3

BC= 1

AC=?

By using Pythagoras theorem;

AC²= AB²+ BC²

AC²= (√3)² + 1²

AC²= 3 + 1

AC²= 4

AC= √4

AC= 2

ii) using tan C = P/B

= √3/1

tan 30°=√3/1

so;

so;angle C= 30°

iii) cosec A= H/P

= 2/1

so;

cosec A = 2

iv) cos C = B/H

=1/2

Cos 30°= 1/2