In a Δ ∠ ABC B , = 90° and AB = 4 cm, BC = 3 cm and AC = 5 cm. Find sinA.
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Given : In ∆ABC
B = 90° , AB=4cm , BC=3cm , AC = 5cm
Now,
sinA = side opposite to A / Hypotenuse
sinA = BC/AC
sibA = 3cm/5cm
sinA = 3/5
i.e.
sinA = 3/5
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Answer:
Step-by-step explanation:
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