In a Δ ∠ ABC B , = 90° and AB = 4 cm, BC = 3 cm and AC = 5 cm. Find sinA.In a Δ ∠ ABC B , = 90° and AB = 4 cm, BC = 3 cm and AC = 5 cm. Find sinA
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5
Answer:
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Answered by
1
Answer:
We have, AB = 4 and BC = 3.
By Pythagoras theorem, we have
AC
2
=AB
2
+BC
2
⇒AC=
AB
2
+BC
2
⇒AC=
4
2
+3
2
=
25
=5
When we consider the t-ratios of ∠A, we have
Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.
∴sinA=
AC
BC
=
5
3
,cosA=
AC
AB
=
5
4
,tanA=
AB
BC
=
4
3
Step-by-step explanation:
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