Question

In A ABC,B-D-C and BD = 7,
BC = 20 find following ratios
A (AABD)
A(AADC)
A (AADC)
b) A(AABC)​

Answer 1

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Theorems: when two triangle are similar the ratio of areas of those triangle is equal to the ratio of the square of their corresponding sides.

1) A(∆ABD) /A(∆ADC)= BD^2/DC^2

BD^2/ (BC-BD)^2

7^2/(20-7)^2

7^2/13^2

2) A(∆ABD)/ A(∆BC)= BD^2/BC^2

BD^2/BC^2

7^2/20^2

3) A(∆ADC ) /A(∆ ABC) = DC^2/BC^2

(BC-BD)^2/BC^2

( 20-7)^2/20^2

13^2/20^2

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Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

theorems: when two triangle are similar the ratio of areas of those triangle is equal to the ratio of the square of their corresponding sides.

1) A(∆ABD) /A(∆ADC)= BD^2/DC^2

BD^2/ (BC-BD)^2

7^2/(20-7)^2

7^2/13^2

2) A(∆ABD)/ A(∆BC)= BD^2/BC^2

BD^2/BC^2

7^2/20^2

3) A(∆ADC ) /A(∆ ABC) = DC^2/BC^2

(BC-BD)^2/BC^2

( 20-7)^2/20^2

13^2/20^2

it's helpful for you