In a ∆abc bc=ac and a
angle B= 64 find angle c
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Answered by
1
let AC = x
BC = x
And angle B = 64
In Triangle ABC
angle (A+B+C)= 180 .
x + 64 + x = 180
2x + 64 = 180
2x = 180 - 64
2x = 116
x=116/2
x = 58.
as we now that AC = BC ; AND we have assumed x ..
So AC = 58
BC = 58.
THANK YOU.
BC = x
And angle B = 64
In Triangle ABC
angle (A+B+C)= 180 .
x + 64 + x = 180
2x + 64 = 180
2x = 180 - 64
2x = 116
x=116/2
x = 58.
as we now that AC = BC ; AND we have assumed x ..
So AC = 58
BC = 58.
THANK YOU.
Answered by
5
Answer:
ac =bc
therefore angle a=angle b [because opposite angle of opposite equal sides are equal]
therefore angle a=64
and angle aplus angle b plus angle c=180
64plus 64 plus angle c=180
therefore angle c=52
Step-by-step explanation:
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