Question

In a ∆abc bc=ac and a
angle B= 64 find angle c

Answer 1

let AC = x
BC = x
And angle B = 64
In Triangle ABC
angle (A+B+C)= 180 .
x + 64 + x = 180
2x + 64 = 180
2x = 180 - 64
2x = 116
x=116/2
x = 58.
as we now that AC = BC ; AND we have assumed x ..
So AC = 58
BC = 58.


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Answer 2

Answer:

ac =bc

therefore  angle a=angle b [because opposite angle of opposite  equal sides are equal]

therefore angle a=64

and angle aplus angle b plus angle c=180

64plus 64 plus angle c=180

therefore angle c=52

Step-by-step explanation: