Question

In A ABC, BD = 2cm, DC = 3 cm. BE = 1.8 cm, AE = 2.7cm. D and E are points on BC and AB respectively check whether DE || AC.​

Answer 1

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Given :-

In triangle ABC, D and E are points on BC and AB such that BD = 2cm, DC = 3 cm. BE = 1.8 cm, AE = 2.7cm.

To prove :-

DE || AC

Concept used :-

The converse of BPT states that "In a triangle, if a line segment intersecting two sides and divides them in the same ratio, then it will be parallel to the third side".

Proof :-

In triangle ️ ABC

BD = 2 cm

DC = 3 cm

BE = 1.8 cm

AE = 2.7cm.

Consider, BD/DC = 2/3

Consider, BE/AE = 1.8/2.7 = 2/3

=> BD/DC = BE/AE

=> By converse of BASIC PROPORTIONALITY THEOREM,

DE || AC.

HENCE, PROVED.

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Answer 2

Answer:

this is correct.....................