Question

In a ∆ABC, C= 3B= (A+B) find the angles of triangle​

Answer 1

Step-by-step explanation:

A+B+C=180

C=A+B

2C=180

C=90

C=3B=90

B=30

A+B=C=90

A+B=90

A=90-30=60

Answer 2

Answer:

A=60°

B=30°

C=90°

Step-by-step explanation:

A+B+C=180° (Theorem-The sum of angles of a triangle is 180°)

2C=180° (Given-A+B=C)

C=90°

3B=C (Given)

B=90°/3

B=30°

A+B+C=180°

A+30°+90°=180°

A=180°-120°

A=60°