Math, asked by Kunju743, 5 months ago

In A ABC, D and E are points AC and BC respectively such that DE
DE || AB. If AD = 2x, BE = 2x – 1, CD = x + 1 and CE = x - 1, then find the value of x.
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Answers

Answered by Anonymous
18

Answer:

ANSWER

The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that AD=8 cm, AB=12 cm and AE=12 cm.

Using the basic proportionality theorem, we have

AB

AD

=

AC

AE

=

BC

DE

AB

AD

=

AC

AE

12

8

=

AC

12

⇒8AC=12×12

⇒8AC=144

⇒AC=

8

144

=18

Now, CE=AC−AE=18−12=6 cm

Hence, CE=6 cm

Answered by aryanthakur34832
8

Answer:

6

Step-by-step explanation:

helpful

plz brainliest

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