Question

In A ABC, DE || AB. If AD = x-3, AC =
2x, BE = x - 2, BC = 2x +3, find the value
of x.​

Answer 1

Step-by-step explanation:

Given, DE II AB

AD=x-3,

BE=x-2,

BC=2x+3,

AC=2x,

AC/AD=BC/BE

2x/x-3=2x+3/x-2

(cross. Multiplication)

(2x)×(x-2)=(x-3)×(2x+3)

2x square-4x=2x square +3-6x-9

(2x square will be cancelled on both sides)

-4x=3x-6x-9

-4x=-3x-9

-4x+3x=-9

-x=-9

('-' will be cancelled on both sides)

Then, x=9