Math, asked by maadesh89, 3 months ago

In a ΔABC, DE || BC. If AD = 1.75 cm, AB = 7 cm and AE = 2cm, then find AC.​

Answers

Answered by cheti3
0

Answer:

according to theorem,

AD / AB = AE / AC

so, 1.75 / 7 = 2 / AC

so, AC = 2 × 7 / 1.75

so, AC = 14 / 1.75

so, AC = 8

Answered by Abhijeet1589
0

Hence, The answer is 8 cm

GIVEN

ΔABC, DE || BC. If AD = 1.75 cm, AB = 7 cm and AE = 2cm

TO FIND

The value of AC

SOLUTION

The above problem came simply solved ad follows;

Given,

ABC is a ∆

DE || BC.

We know that, if a line parallel to to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.

Then;

AD/ DB = AE/EC

Where,

AD = 1.75 cm

AB = 7 cm

DB = 7 - 1.75 = 5.25 cm

AE = 2cm

Putting the values;

1.75/5.25 = 2/EC

EC = (5.25 × 2)/1.75

= 10.5/1.75

= 6cm

AC = 6 + 2 = 8cm

Hence, The answer is 8 cm

#SPJ2

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