In a ΔABC, DE || BC. If AD = 1.75 cm, AB = 7 cm and AE = 2cm, then find AC.
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Answer:
according to theorem,
AD / AB = AE / AC
so, 1.75 / 7 = 2 / AC
so, AC = 2 × 7 / 1.75
so, AC = 14 / 1.75
so, AC = 8
Answered by
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Hence, The answer is 8 cm
GIVEN
ΔABC, DE || BC. If AD = 1.75 cm, AB = 7 cm and AE = 2cm
TO FIND
The value of AC
SOLUTION
The above problem came simply solved ad follows;
Given,
ABC is a ∆
DE || BC.
We know that, if a line parallel to to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.
Then;
AD/ DB = AE/EC
Where,
AD = 1.75 cm
AB = 7 cm
DB = 7 - 1.75 = 5.25 cm
AE = 2cm
Putting the values;
1.75/5.25 = 2/EC
EC = (5.25 × 2)/1.75
= 10.5/1.75
= 6cm
AC = 6 + 2 = 8cm
Hence, The answer is 8 cm
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