In a ∆ABC,DE is parallel to BC and D is the mid-point of side AB.Find AE and BC if DE=6 cm and EC=5 cm.
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Answer: BC = 12cm, AE = 5cm
Step-by-step explanation:
In Triangle ABC, D is mid pt. of AB and DE II BC.
Therefore, E is mid pt. of AC ( Mid Point Theorm)
Therefore, AE = EC = 5cm
DE = 6cm (given)
Therefore, since DE II Bc and D is mid point of AB, BC = 2DE
=> BC = 2 X 6 = 12cm
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