In a ∆abc , de parallel BC and ad = X+3 dB= 3x +19 ,ae= X and CE = 3x + 3 , then find X.
Answers
Answered by
0
Answer:
In a ∆abc , de parallel BC and ad = X+3 dB= 3x +19 ,ae= X and CE = 3x + 3 , then find X.
Similar questions