Math, asked by xD000, 8 months ago

In a ∆ABC, if 2 ∠A = 3 ∠B = 6 ∠C then calculate  ∠A,  ∠B and  ∠C.​

Answers

Answered by hardeepaircondition
0

Answer:

Please show the diagram

Please make it Brainliest answer

Answered by Disha976
15

Answer:

Let  2 ∠A = 3 ∠B = 6 ∠C = x°

Then,

 ∠A = ( \frac{x}{2}° ) ;∠B = ( \frac{x}{3} °)and \: ∠C =(  \frac{x}{6}° )

 But , ∠A + ∠B + ∠C = 180°

 .°. \frac{x}{2} +  \frac{x}{3} +  \frac{x}{6} = 180

 \implies 3x + 2x + x = 1080

 \implies 6x = 1080

 \implies x = \frac {1080}{6} = 180

 .°.  ∠A = \frac { 180}{2}°= 90°

 .°.  ∠B = \frac { 180}{3}°= 60°

 .°.  ∠C = \frac { 180}{6}°= 30°

Hence, ∠A = 90° , ∠B = 60° and ∠C = 30°

Hope it helps♥.

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