Question

In a ∆ABC. if 3∆A=4,∆B = 6∆C, calculate the angles.​

Answer 1

Answer:

rhhvbbgbb

Step-by-step explanation:

fhhgffgh er gh

Answer 2

Answer:

Let 3∠A=4∠B=6∠C=x

∠A=

3

x

,∠B=

4

x

,∠C=

6

x

∠A+∠B+∠C=180

∘

3

x

+

4

x

+

6

x

=180

∘

x=240

∘

Therefore,

∠A=80

∘

,∠B=60

∘

∠C=40

∘