In a ∆ABC, if 3∠A = 4∠B = 6∠C then A: B : C = ?
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Answer:
Let 3∠A=4∠B=6∠C=x
∠A=
3
x
,∠B=
4
x
,∠C=
6
x
∠A+∠B+∠C=180 Let 3∠A=4∠B=6∠C=x
∠A=
3
x
,∠B=
4
x
,∠C=
6
x
∠A+∠B+∠C=180
∘
3
x
+
4
x
+
6
x
=180
∘
x=240
∘
Therefore,
∠A=80
∘
,∠B=60
∘
∠C=40
∘
3
x
+
4
x
+
6
x
=180
∘
x=240
∘
Therefore,
∠A=80
∘
,∠B=60
∘
∠C=40
∘
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