In a Δ ABC, if ∠A =120° and AB=AC. Find ∠B and ∠C.
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Given : In a Δ ABC, ∠A = 120° and AB = AC
Δ ABC is an isosceles triangle since AB = AC
∠ B = ∠ C ……… (1)
[Angles opposite to equal sides are equal]
We know, that sum of angles in a triangle is 180°.
∠ A + ∠ B + ∠ C = 180°
∠ A + ∠ B + ∠ B = 180°
[From eq (1)]
120° + 2∠B = 180°
2∠B = 180° – 120°
2∠B = 60°
∠B = 60°/2
∠ B = 30°
Hence, ∠ B = ∠ C = 30°
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