In A ABC, if a = 13, b = 14, c = 15, then the area
of the incircle is
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MATHS
If a=13,b=14,c=15 then area of incircle is
ANSWER
r=
s
Δ
tan(A/2)=
s(s−a)
Δ
Δ=
(
2
13+14+15
)(
2
(13+14−15)
)(
2
(13+15−14)
)(
2
(14+15−13)
)
=
16
42×12×14×16
=84
s=21
r=
21
84
r=4
Area A=πr
2
=π×16
=50.265
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