Math, asked by Scholar12345, 3 months ago

In a ∆ ABC , if ∠A=∠B=2C,Find each of the angles...please answers this question​

Answers

Answered by MatrixMentor
5

Step-by-step explanation:

In a ∆ ABC , if ∠A=∠B=2C,Find each of the angles...please answers this

Attachments:
Answered by BrainlyMan05
42

Answer:

\angle{A} = 72°

\angle{B} = 72°

\angle{C} = 36°

Step-by-step explanation:

Question:

In a ∆ ABC , if ∠A=∠B=2C, Find each of the angles...

Given:

  • ∠A=∠B=2C

To find:

  • Each of the angles

Angle sum property:

According to the Angle sum property:-

The sum of three angles of a triangle is 180°

That means, \angle{A} + \angle{B} + \angle{C} = 180°

Solution:

Since, \angle{A} = 2 \times \angle{C}

\angle{B} = 2 \times \angle{C}

We need to substitute the value of Angle A and B as 2C in the following property:-

\angle{A} + \angle{B} + \angle{C} = 180°

2\angle{C} + 2\angle{C} + \angle{C} = 180°

5\angle{C} = 180°

\angle{C} = \dfrac{180}{5}

\angle{C} = 36°

Since \angle{C} is 36°, \angle{A} and \angle{B} are:

2\angle{C} = 2 \times 36°

= 72°

Final answer:

\angle{A} = 72°

\angle{B} = 72°

\angle{C} = 36°

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