in a ∆abc if a-b=40° b-c=10° find measure of angles a,b and c
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Answered by
9
A - B = 40°
A = 40° + B
B - C = 10°
B - 10° = C
A + B + C = 180°
40° + B + B + B - 10° = 180°
3B + 30° = 180°
3B = 180° - 30°
B = 150°/3 = 50°
A = 40° + B = 40° + 50° = 90°
B = 50°
C = B - 10° = 50° - 10° = 40°
A = 40° + B
B - C = 10°
B - 10° = C
A + B + C = 180°
40° + B + B + B - 10° = 180°
3B + 30° = 180°
3B = 180° - 30°
B = 150°/3 = 50°
A = 40° + B = 40° + 50° = 90°
B = 50°
C = B - 10° = 50° - 10° = 40°
sara99:
thank you
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6
hey dear,
refer to given attachment please
refer to given attachment please
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