In a ΔABC, if ∠A – ∠B = 420
and ∠B – ∠C = 210
, then the measure of ∠B is:
Answers
Answer:
angle B = 53°.
Step-by-step explanation:
A+B+C= 180°
180-42+21=159°
therefore B=53°✓✓✓✓✓ mark me as brainliest
The measure of ∠B is 53°
Given :
In a ΔABC, if ∠A – ∠B = 42° and ∠B – ∠C = 21°
To find :
The measure of ∠B
Solution :
Step 1 of 2 :
Write down the given data
In a ΔABC,
∠A – ∠B = 42° - - - - - (1)
∠B – ∠C = 21° - - - - - - (2)
Step 2 of 3 :
Find sum of three angles
We know that for a triangle ΔABC
∠A + ∠B + ∠C = 180°
⇒ ∠A + ∠C = 180° - ∠B - - - - - (3)
Step 3 of 3 :
Find measure of ∠B
Equation 1 - Equation 2 gives
∠A - 2∠B + ∠C = 21° - - - - (4)
From Equation 3 and Equation 4 we get
180° - ∠B - 2∠B = 21°
⇒ 3∠B = 159°
⇒ ∠B = 53°
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