Question

In a ∆ ABC, if ےA: ےB: ےC = 3: 2: 1, determine ےA, ےB, ےC​

Answer 1

Answer:

We have,

1st angle = 45°

2nd angle = 70°

3rd angle = ?

Let's find 3rd angle of triangle.

\begin{gathered} \\ \qquad \sf \angle \: A = 45 \: \: \: and \: \: \: \angle \: B = 70 \\ \\ \\ \therefore \: \: \sf \angle \: A + \angle \: B + \angle \: C = 180 \\ \\ \\ \implies \sf45 + 70 + \angle \: C = 180 \\ \\ \\ \implies \sf \angle \: C = 180 - 115 \\ \\ \\ \implies \boxed{ \sf \angle \:C = 65} \\ \\ \end{gathered}

∠A=45and∠B=70

∴∠A+∠B+∠C=180

⟹45+70+∠C=180

⟹∠C=180−115

⟹

∠C=65

Since the side opposite to the greatest side is largest. Therefore, side AC is largest.

The side opposite to the least angle is the smallest. So, side opposite to A i.e BC is the smallest.